x(2x^2+3xy+y^2)-y(5x^2-2xy+y^2)=0

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Solution for x(2x^2+3xy+y^2)-y(5x^2-2xy+y^2)=0 equation: 


Simplifying
x(2x2 + 3xy + y2) + -1y(5x2 + -2xy + y2) = 0

Reorder the terms:
x(3xy + 2x2 + y2) + -1y(5x2 + -2xy + y2) = 0
(3xy * x + 2x2 * x + y2 * x) + -1y(5x2 + -2xy + y2) = 0

Reorder the terms:
(xy2 + 3x2y + 2x3) + -1y(5x2 + -2xy + y2) = 0
(xy2 + 3x2y + 2x3) + -1y(5x2 + -2xy + y2) = 0

Reorder the terms:
xy2 + 3x2y + 2x3 + -1y(-2xy + 5x2 + y2) = 0
xy2 + 3x2y + 2x3 + (-2xy * -1y + 5x2 * -1y + y2 * -1y) = 0
xy2 + 3x2y + 2x3 + (2xy2 + -5x2y + -1y3) = 0

Reorder the terms:
xy2 + 2xy2 + 3x2y + -5x2y + 2x3 + -1y3 = 0

Combine like terms: xy2 + 2xy2 = 3xy2
3xy2 + 3x2y + -5x2y + 2x3 + -1y3 = 0

Combine like terms: 3x2y + -5x2y = -2x2y
3xy2 + -2x2y + 2x3 + -1y3 = 0

Solving
3xy2 + -2x2y + 2x3 + -1y3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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